INFO: Rotating a Bitmap by 90 Degrees (77127)
The information in this article applies to:
- Microsoft Windows Software Development Kit (SDK) 3.1
- Microsoft Windows Software Development Kit (SDK) 3.0
- Microsoft Win32 Application Programming Interface (API), when used with:
This article was previously published under Q77127 SUMMARY
There are no Windows functions that directly rotate bitmaps. All techniques
for rotating bitmaps in Windows involve copying the rows from a source
bitmap into the columns of a destination bitmap. The following contains
code for rotating a bitmap using GetPixel() and SetPixel(), and contains an outline of code for rotating device independent bitmaps (DIB).
MORE INFORMATION
A device dependent bitmap (DDB) can be rotated using the GetPixel() and SetPixel() functions. To rotate the bitmap, use the following code:
HBITMAP Rotate90(HDC hDC, HBITMAP hSourceBitmap)
{
HBITMAP hOldSourceBitmap, hOldDestBitmap, hDestBitmap;
HDC hMemSrc, hMemDest;
int height, width;
int i, j;
BITMAP iSrcBitmap;
// Step 1: Create a memory DC for the source and destination bitmaps
// compatible with the device used.
hMemSrc = CreateCompatibleDC(hDC);
hMemDest= CreateCompatibleDC(hDC);
// Step 2: Get the height and width of the source bitmap.
GetObject(hSourceBitmap, sizeof(BITMAP), (LPSTR)&SrcBitmap);
width = SrcBitmap.bmWidth;
height = SrcBitmap.bmHeight;
// Step 3: Select the source bitmap into the source DC. Create a
// destination bitmap, and select it into the destination DC.
hOldSourceBitmap = SelectObject(hMemSrc, hSourceBitmap);
hDestBitmap = CreateBitmap(height, width, SrcBitmap.bmPlanes,
SrcBitmap.bmBitsPixel, NULL);
if (!hDestBitmap)
return(hDestBitmap);
hOldDestBitmap = SelectObject(hMemDest, hDestBitmap);
// Step 4: Copy the pixels from the source to the destination.
for (i = 0; i < width; ++i)
for (j = 0; j < height; ++j)
SetPixel(hMemDest, j, width - 1 - i,
GetPixel(hMemSrc, i, j));
// Step 5: Destroy the DCs.
SelectObject(hMemSrc, hOldSourceBitmap);
SelectObject(hMemDest, hOldDestBitmap);
DeleteDC(hMemDest);
DeleteDC(hMemSrc);
// Step 6: Return the rotated bitmap.
return(hDestBitmap);
}
If the bitmap is larger, using GetPixel() and SetPixel() may be too slow. If this is the case, there are two options:
- If the contents of the bitmap do not change, create two versions of
the bitmap, the normal version and one that is rotated by 90
degrees. Load the appropriate bitmap as required.
-or-
- Find some way to manipulate the bits of the bitmap that is faster than using SetPixel() and GetPixel(). The best way to do this is to convert the bitmap to a device independent bitmap. The following four steps detail how to create the DIB and to perform the rotation:
- Use GetDIBits() to convert the bitmap to a device independent format. It is necessary to create a BITMAPINFO structure appropriate for the bitmap. This will write the bitmap as a series of scanlines. Each scanline is padded so that it is DWORD aligned.
- Allocate memory for the destination bitmap. This bitmap requires
as many scanlines as the width of the source bitmap. Each
scanline is as many pixels wide as the height of the source
bitmap. Also, the scanlines must be DWORD aligned.
- For each scanline in the source bitmap, copy the pixels to the
appropriate column in the destination bitmap. NOTE: The format
for each scanline depends upon the number of bits per pixel. See
the BITMAPINFO documentation for a description of the possible
formats.
- Use SetDIBits() to copy the device independent bits into a
device dependent bitmap. Another BITMAPINFO structure,
appropriate for the destination device is required for this
step.
The four steps of this method require much more work than is required
if GetPixel() and SetPixel() are used; however, this method may be faster because it directly manipulates the bits in the bitmap.
Modification Type: | Minor | Last Reviewed: | 2/11/2005 |
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Keywords: | kbinfo KB77127 |
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