"Overflow" with Integer Division and MOD Operator; Workaround (58499)

SUMMARY

The integer division operator (\) and the modulo arithmetic operator (MOD) correctly produce an "Overflow" error if an operand is a negative number less than -2,147,483,648 or a positive number greater than +2,147,483,647 (outside the limits for long integers).

The following program shows how to do integer division and modulo arithmetic when the size of an operand causes overflow:

   x# = 2147483648                ' numerator
   y# = 123                       ' denominator
   x# = INT(x# + .5)              ' round off the numerator
   y# = INT(y# + .5)              ' round off the denominator
   PRINT FIX(x# / y#)             ' Emulate integer division
   PRINT x# - ( y# * FIX(x# / y#) )  ' Emulate modulo arithmetic