INFO: Initializing Unions Initializes First Member of the Union (47693)



The information in this article applies to:

  • Microsoft C for MS-DOS
  • Microsoft Visual C++ 1.0
  • Microsoft Visual C++ 1.5
  • Microsoft Visual C++ 1.51
  • Microsoft Visual C++ 1.52
  • Microsoft Visual C++ 2.0
  • Microsoft Visual C++ 2.1
  • Microsoft Visual C++ 4.0
  • Microsoft Visual C++, 32-bit Enterprise Edition 5.0
  • Microsoft Visual C++, 32-bit Enterprise Edition 6.0
  • Microsoft Visual C++, 32-bit Professional Edition 5.0
  • Microsoft Visual C++, 32-bit Professional Edition 6.0
  • Microsoft Visual C++, 32-bit Learning Edition 6.0

This article was previously published under Q47693

SUMMARY

When initializing a union, the initialization value is applied to the first member of the union even if the type of the value matches a subsequent member. As stated in the ANSI Standard, Section 3.5.7:
   A brace-enclosed initializer for a union object initializes the
   member that appears first in the declaration list of the union
   type.
				
Because you cannot initialize the value of any member of a union other than the first one, you must assign their values in a separate statement. Initializing a union with a value intended for a subsequent member causes that value to be converted to the type of the first member.

MORE INFORMATION

The following example demonstrates the issue:

Sample Code

/* Compile options needed: none
*/ 

#include <stdio.h>
union { int   a;
        float b;
      } test = {3.6};    /* This is intended to initialize 'b'      */ 
                         /* however, the value will be converted    */ 
                         /* (first to a long and then to an int)    */ 
                         /* in order to initialize 'a'.             */ 

void main (void)
{
   float dummy = 0.0;            /* This causes the floating point  */ 
                                 /* math package to be initialized.  */ 
                                 /* Not necessary with VC++ for     */ 
                                 /* Windows NT.                      */ 

   printf ("test.a = %d,  test.b = %f\n", test.a, test.b);
}
				
The output from the example, though not what is intended, is as follows:
   test.a = 3, test.b = 0.00000
				
To associate a value with "b", you can reverse the order of the members, as in the following:
union {
        float b;
        int a;
      } test = {3.6};
				
Or, you can retain the order of the elements and assign the value in a separate statement, as in the following:
   test.b = 3.6;
				
Either of these methods creates the following output:
   test.a = 26214, test.b = 3.600000
				
Under Windows NT, the output would be as follows:
   test.a = 1080452710, test.b = 3.600000
				

REFERENCES

For examples and explanation of possible compiler errors and warnings generated when attempting to initialize a non-primary union element, please see the following article in the Microsoft Knowledge Base:

39910 PRB: Initializing Non-Primary Union Element Produces Errors


Modification Type:MinorLast Reviewed:7/5/2005
Keywords:kbcode kbinfo kbLangC KB47693