BUG: ClassView does not show all methods for an interface in Visual C++ 6.0 (247713)

HRESULT MyMethod(BYTE * p);
				

HRESULT MyMethod(PBYTE p);
				

struct MyStruct
{
   int i;
};
...
interface IMyIF
{
   HRESULT MyMethod(struct MyStruct * pMyStruct);
}
				

typedef struct MyStruct_tag
{
   int i;
} MyStruct;
...
interface IMyIF
{
   HRESULT MyMethod(MyStruct * pMyStruct);
}
				

MORE INFORMATION

Even though two types are logically equivalent, ClassView sees them as different since the syntax is different. If the .idl file explicitly specifies a class or structure in a parameter type declaration, a bug in ClassView's parser strips the word "class" or "struct" from the declaration. Since in either of these cases the interface and implementation declarations no longer match according to ClassView, it displays the method outside of the interface.

Steps to reproduce the behavior

1. Create a default ATL COM AppWizard project. In this example, it is named MyProj.
2. In ClassView, right-click the MyProj classes node. Select New class.
3. In the New Class dialog box, select ATL Class as the class type, and type CMyIF for the class name. Click OK.
4. Right-click the interface in ClassView and select Add Method.
5. In the Add Method to Interface dialog box, type MyMethod for Method name, and type struct MyStruct for Parameters. Click OK.
6. In ClassView, click the + to expand the MyProj classes node, the CMyIF node, the IMyIF node inside it that has just been revealed, and the IMyIF node at the same level as CMyIF.

The method MyMethod appears as a member of CMyIF, rather than as a member of the implemented IMyIF. The "struct" has been stripped off. However, MyMethod displays properly in the IMyIF interface definition node.