FIX: UPDATE of Table Column with a FOREIGN KEY Constraint May Fail with Msg 8623 (214818)
The information in this article applies to:
This article was previously published under Q214818
BUG #: 53943 (SQLBUG_70)
SYMPTOMS
Attempting to update a column using a declared variable may fail if that column has a FOREIGN KEY (FK) constraint and the FROM clause references multiple tables. In such cases, the following error message occurs:
Server: Msg 8623, Level 16, State 2, Line 8
Internal Query Processor Error: The query processor could not produce a query plan.
For example, the following would cause the error:
declare @c1 int
select @c1 =
update secondary_tbl set c1 = @c1
from secondary_tbl p,child_1 t1, child_2 t2
where p.s1 = t1.s1
WORKAROUND
To work around this problem, use CONVERT to cast the variable to its data type. In the preceding example, replace:
update secondary_tbl set c1 = @c1
with:
update secondary_tbl set c1 = convert(int,@c1)
STATUS
Microsoft has confirmed this to be a problem in SQL Server 7.0. This problem has been corrected in U.S. Service Pack 2 for Microsoft SQL Server 7.0. For more information, click the following article number to view the article in the Microsoft Knowledge Base: 254561 INF: How to Obtain Service Pack 2 for Microsoft SQL Server 7.0 and Microsoft Data Engine (MSDE) 1.0 For more information, contact your primary support provider.
Modification Type: | Major | Last Reviewed: | 3/14/2006 |
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Keywords: | kbBug kbfix KB214818 |
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