How to store, calculate, and compare Date/Time data in Microsoft Access (210276)

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Store Date/Time data

Access stores the Date/Time data type as a double-precision, floating-point number up to 15 decimal places. The integer part of the double-precision number represents the date. The decimal portion represents the time.

Valid date values range from -657,434 (January 1, 100 A.D.) to 2,958,465 (December 31, 9999 A.D.). A date value of 0 represents December 30, 1899. Access stores dates before December 30, 1899 as negative numbers.

Valid time values range from .0 (00:00:00) to .99999 (23:59:59). The numeric value represents a fraction of one day. You can convert the numeric value to hours, to minutes, and to seconds by multiplying the numeric value by 24.

The following table shows how Access stores Date/Time values:

   Double         Date      Actual             Time      Actual
   number         portion   date               portion   time
   ------------------------------------------------------------------

        1.0           1     December 31, 1899  .0        12:00:00 A.M.
        2.5           2     January 1, 1900    .5        12:00:00 P.M.
    27468.96875   27468     March 15, 1975     .96875    11:15:00 P.M.
    36836.125     36836     November 6, 2000   .125       3:00:00 A.M.
				

To view how Access stores Date/Time values as numbers, type the following commands in the Immediate window, press ENTER, and then notice the results: Result equals: 36298.5833333333 Result equals: -18278.7305555556

To view the date and the time of numeric values, type the following commands in the Immediate window, press ENTER, and then notice the results:
Result equals: 12/31/1899 9:00:00 AM Result equals: 8/1/1066 1:48:00 PM

Format a Date/Time field

You can format a Date/Time value to display a date, a time, or both. When you use a date-only format, Access stores a value of 0 for the time portion. When you use a time-only format, Access stores a value of 0 for the date portion.

The following table shows how Access stores Date/Time values. The following table also shows how you can display those values by using different formats:

   Stored value            Default format    Custom format
   (double number)         (General Date)    (mm/dd/yyyy hh:nn:ss A.M./P.M.)
   ---------------------------------------------------------------------

   36295.0                 5/15/99           05/15/1999 12:00:00 AM
       0.546527777777778   1:07 PM           12/30/1899 01:07:00 PM
   36232.9375              3/13/99 10:30PM   03/13/1999 10:30:00 PM
				

Note The default format for a Date/Time value is General Date. If a value is date-only, no time appears. If the value is time-only, no date appears.

Calculate time data

Because a time value is stored as a fraction of a 24-hour day, you may receive incorrect formatting results when you calculate time intervals greater than 24 hours. To work around this behavior, you can create a user-defined function to make sure that time intervals are formatted correctly.

Microsoft provides programming examples for illustration only, without warranty either expressed or implied. This includes, but is not limited to, the implied warranties of merchantability or fitness for a particular purpose. This article assumes that you are familiar with the programming language that is being demonstrated and with the tools that are used to create and to debug procedures. Microsoft support engineers can help explain the functionality of a particular procedure, but they will not modify these examples to provide added functionality or construct procedures to meet your specific requirements. To correctly calculate and to format time intervals, follow these steps:

1. Create a module, and then type the following line in the Declarations section if the following line is not already there:

   Option Explicit
   					

2. Type the following procedure:

   '------------------------------------------------------------------
   '  This function calculates the elapsed time between two values and then 
   '  formats the result in four different ways.
   '
   '  The function accepts interval arguments such as the following:
   '
   '     #5/12/95 6:00:00AM# - #5/11/95 10:00:00PM#
   '
   '     
   '
   '     [End Time]-[Start Time]
   '------------------------------------------------------------------
   
   Function ElapsedTime (Interval)
     Dim x
     x = Int(CSng(Interval * 24 * 3600)) & " Seconds"
     Debug.Print x
     x = Int(CSng(Interval * 24 * 60)) & ":" & Format(Interval, "ss") _
        & " Minutes:Seconds"
     Debug.Print x
     x = Int(CSng(Interval * 24)) & ":" & Format(Interval, "nn:ss") _
        & " Hours:Minutes:Seconds"
     Debug.Print x
     x = Int(CSng(Interval)) & " days " & Format(Interval, "hh") _
        & " Hours " & Format(Interval, "nn") & " Minutes " & _
        Format(Interval, "ss") & " Seconds"
     Debug.Print x
   
   End Function
   					

3. Type the following line in the Immediate window, and then press ENTER:

   ? ElapsedTime(#6/1/1999 8:23:00PM#-#6/1/1999 8:12:12AM#)

   Notice that the following values appear:

   43848 Seconds
   730:48 Minutes:Seconds
   12:10:48 Hours:Minutes:Seconds
   0 days 12 Hours 10 Minutes 48 Seconds

Compare date data

Because dates and times are stored together as double-precision numbers, you may receive unexpected results when you compare Date/Time data. For example, if you type the following expression in the Immediate window, you receive a False result even if today's date is 3/31/1999: The Now() function returns a double-precision number that represents the current date and the current time. However, the DateValue() function returns an integer number that represents the date but not a fractional time value. Therefore, Now() equals DateValue() only when Now() returns a time of 00:00:00 (12:00:00 A.M.).

To receive accurate results when you compare date values, use one of the following functions. To test each function, type the function in the Immediate window, substitute the current date for 3/31/1999, and then press ENTER:

• To return an integer value, use the Date() function:

  ?Date()=DateValue("3/31/1999")

• To remove the fractional part of the Now() function, use the Int() function:

  ?Int(Now())=DateValue("3/31/1999")

Compare time data

When you compare time values, you may receive inconsistent results because a time value is stored as the fractional part of a double-precision, floating-point number. For example, if you type the following expression in the Immediate window, you receive a false (0) result even though the two time values look the same: When Access converts a time value to a fraction, the calculated result may not be identical to the time value. The small difference caused by the calculation is sufficient to produce a false (0) result when you compare a stored value to a constant value.

To receive accurate results when you compare time values, use one of the following methods. To test each method, type each method in the Immediate window, and then press ENTER:

Add an associated date to the time comparison:Convert the time values to string data types before you compare them:Use the DateDiff() function to compare precise units such as seconds: