FIX: printf Does Not Recognize "\n\r" when Using Conversion (117385)

The information in this article applies to:

The C Run-Time (CRT), when used with:
- Microsoft Visual C++ 1.0
- Microsoft Visual C++ 1.5

This article was previously published under Q117385

SYMPTOMS

If an explicit type-conversion syntax is used for the return value of printf(), printf() does not recognize the escape sequence \n\r in its format string.

The following macro prints "<string x>\n\r":

   #define PRINT(x) void( printf("%s\n\r", x ) )

RESOLUTION

To correct the error, use one of the following workarounds:

Use ASCII values for the line feed and carriage return. For example:

      #define PRINT(x)  void( printf("%s%c%c",x,10,13 ) )

-or-

Use explicit typecasting instead. For example:

      #define PRINT(x)  (void)( printf("%s\n\r",x ) )

-or-

Program without the conversion or casting if possible. For example:
```
      #define PRINT(x)  printf("%s\n\r", x )
						
```

STATUS

Microsoft has confirmed this to be a bug in the products listed at the beginning of this article. This problem was corrected in Visual C++ 32-bit Edition, version 2.0.

Modification Type:	Major	Last Reviewed:	11/18/2003
Keywords:	kbbug kbCRT kbfix KB117385