INFO: sizeof(char Expression) Same as sizeof(int) (68389)

MORE INFORMATION

This is ANSI-specified behavior. Below is Section 3.3.7 from the ANSI specifications, which details the semantics of the shift operator: This means that chars are promoted to integers by default. If you really want a char result, you must cast the final result.

The ANSI-specified semantics of all operators specify promotion from char to int, so the size of any char expression will be the sizeof int. This was also the case for Kernighan and Ritchie (K & R) C.

The sizes of the int and long expressions stay the same because no promotion takes place.

Note that if int is the same size as long rather than short in this implementation, the sizeof both a short expression and a char expression will be 4, as will be the sizeof both an int and a long expression.

Sample Code

/* Compile options needed: none
*/ 

#include <stdio.h>

void main(void)
{
   short si;
   long li;
   char sc;
   unsigned char uc;

   printf("Signed char width: %d\n",
           sizeof((char)(sc<<1)));          // 1 byte

   printf("Signed char width: %d\n",
           sizeof(sc<<1));                 // 2 bytes

   printf("Unsigned char width: %d\n",
           sizeof((unsigned char)uc<<1));  // 2 bytes

   printf("Unsigned char width: %d\n",
           sizeof(uc<<1));                 // 2 bytes

   printf("Short width: %d\n",
           sizeof(si<<1));                 // 2 bytes

   printf("Long width: %d\n",
           sizeof(li<<1));                 // 4 bytes
}