Conversion to Base x Function Not Available (140035)



The information in this article applies to:

  • Microsoft Excel 97 for Windows
  • Microsoft Excel for Windows 95
  • Microsoft Excel for Windows 5.0
  • Microsoft Excel 98 Macintosh Edition

This article was previously published under Q140035

SYMPTOMS

Microsoft Excel version 4.0 includes an add-in function named BASE() which accepts input for a base 10 number and a number designating the base to which it should be converted. BASE() outputs a text string representation of the number in that base. For example, BASE() converts the number 5 in base 10 to the string 101 if you request base 2.

Microsoft Excel versions 5.0 and later do not include the BASE() function. When you open a workbook in Microsoft Excel version 5.0 or later, you receive a "#NAME" error in the cells that contain the BASE() function.

MORE INFORMATION

Microsoft provides programming examples for illustration only, without warranty either expressed or implied. This includes, but is not limited to, the implied warranties of merchantability or fitness for a particular purpose. This article assumes that you are familiar with the programming language that is being demonstrated and with the tools that are used to create and to debug procedures. Microsoft support engineers can help explain the functionality of a particular procedure, but they will not modify these examples to provide added functionality or construct procedures to meet your specific requirements. The following sample Microsoft Visual Basic for Applications function is a simple base function similar to the Microsoft Excel 4.0 BASE() function. This example does not perform any decimal conversion.

Sample Visual Basic Procedure

   Function Base(InValue As Double, NewBase As Double) As String
       Dim TestVal As Double, counter As Integer, Alpha As String
       Dim Holder As Integer
       Application.Volatile
       On Error GoTo FixError
       If InValue = 0 Then GoTo FixError
       If NewBase = 0 Then GoTo FixError
       counter = 0
       TestVal = 0
       While TestVal < InValue
           TestVal = NewBase ^ counter
           If TestVal < InValue Then counter = counter + 1
       Wend
       counter = counter - 1
       Alpha = ""
       Holder = 0
       For x = counter To 0 Step -1
           Holder = Int(InValue / (NewBase ^ x))
           Alpha = Alpha & Application.Text(Holder, "0")
           InValue = InValue - (Holder * (NewBase ^ x))
       Next x
       Base = Alpha
       Exit Function
   FixError:
       Base = "#Value"
   End Function
				

Modification Type:MinorLast Reviewed:10/11/2006
Keywords:kbdtacode kberrmsg kbhowto kbProgramming KB140035